## showing its a subspace |
lilb |
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What do we have to do to show that something is a subspace? |

DonnaBranchevsky: June 5, 2015, 5:38 p.m. |
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Show that it is closed under addition and multiplication, and that it contains the zero vector. |

Jerry_Zhongyang_Liu: June 5, 2015, 8:45 p.m. |
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Suppose we have a linear transformation T: V->R A subspace has the following properties: Suppose we have vector v and w from V 1. closed under addition: T(v+w) = T(v) + T(w) 2. closed under scalar multiplication: Let c be any real constant T(cv) = cT(v) 3. Contains zero vector |