showing its a subspace
lilb
What do we have to do to show that something is a subspace?
DonnaBranchevsky: June 5, 2015, 5:38 p.m.
Show that it is closed under addition and multiplication, and that it contains the zero vector.
Jerry_Zhongyang_Liu: June 5, 2015, 8:45 p.m.
Suppose we have a linear transformation T: V->R A subspace has the following properties: Suppose we have vector v and w from V 1. closed under addition: T(v+w) = T(v) + T(w) 2. closed under scalar multiplication: Let c be any real constant T(cv) = cT(v) 3. Contains zero vector