Practice Midterm #2 Solution
yangfang84
rref(A)= 1 0 0 -7/6 0 1 0 17/3 0 0 1 -1/2 Dim(im(A))= 3 Dim(ker(A))= 4-3=1 Ker(A)= 7/6 -17/3 1/2 1
yangfang84: May 6, 2015, 1:30 a.m.
For a better format: rref(A)=first row: 1 0 0 -7/6 second row: 0 1 0 17/3 third row: 0 0 1 -1/2 Dim(im(A))= 3 Dim(ker(A))= 4-3=1 Ker(A)= first row: 7/6 second row:-17/3 third row: 1/2 fourth row: 1