Practice Midterm 33A #8
Jackhe
Anyone else get [ \left( \begin{array}{ccc} \frac{1}{2} & -1 & 1 \\ 1 & 1 & 1 \\ 0 & 0 & -2 \end{array} \right)\]
danielkim: May 5, 2015, 12:58 a.m.
I got a similar answer to what you got, but our column vectors are rearranged. https://www.camscanner.com/share/dtwLx/0/w105s0byiu0da
Jackhe: May 5, 2015, 9:14 a.m.
Yeah, I found a mistake