## Practice Final B11 |
adikantawala |
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How would this problem be done if they asked for the max instead of the min? |

Lilyhui: March 19, 2015, 5:20 p.m. |
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Asking for max is an easier problem to do because you don't have to find the compliment (which you have to do if the question asks for min) You would approach the question by just multiplying P(x<x) and P(y<x) and solving the problem in a similar fashion as with finding the min :) |

weisbart: March 20, 2015, 1:24 a.m. |
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Exactly! |